![]() If you stick to abstract classes, you will never run into this problem. Method, the implementation of the class will be used instead of Also if the class implements an interface's default Method, then the diamond problem occurs and the compiler rejects theĬompilation. And if there are multiple default implementations of a To patch the missing implementation(s) with interface's default Optional methods of its interfaces, the code can be compiled and the Implementation is used: only if the class implements all default / To address the diamond problem there is a precedence in which order an The resolution tactic now is a little complicated, but here is a good description of it: This was never an issue in Java 7-, since you could only extend one class and interfaces had no methods. The problem occurs when you inherit from two places that declare the same method, and you have to pick one when resolving a function call. The problem is described here (and many other places) In this article, Orace defends the distinction between the two type systemsĮDIT To clarify the "diamond problem" bullet This enables you to define methods that can access and modify the state of the
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